b^2+4=4b

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Solution for b^2+4=4b equation:


Simplifying
b2 + 4 = 4b

Reorder the terms:
4 + b2 = 4b

Solving
4 + b2 = 4b

Solving for variable 'b'.

Reorder the terms:
4 + -4b + b2 = 4b + -4b

Combine like terms: 4b + -4b = 0
4 + -4b + b2 = 0

Factor a trinomial.
(2 + -1b)(2 + -1b) = 0

Subproblem 1

Set the factor '(2 + -1b)' equal to zero and attempt to solve: Simplifying 2 + -1b = 0 Solving 2 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1b = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1b = 0 + -2 -1b = 0 + -2 Combine like terms: 0 + -2 = -2 -1b = -2 Divide each side by '-1'. b = 2 Simplifying b = 2

Subproblem 2

Set the factor '(2 + -1b)' equal to zero and attempt to solve: Simplifying 2 + -1b = 0 Solving 2 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1b = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1b = 0 + -2 -1b = 0 + -2 Combine like terms: 0 + -2 = -2 -1b = -2 Divide each side by '-1'. b = 2 Simplifying b = 2

Solution

b = {2, 2}

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